🎓 Prepared by students from Boğaziçi University

What is Hardy-Weinberg Equilibrium?

Hardy-Weinberg equilibrium is a fundamental population genetics model that predicts how allele and genotype frequencies stay constant across generations when no evolutionary forces act. It gives biologists a mathematical baseline for detecting when evolution is actually happening in a population.

Short answer

Hardy-Weinberg equilibrium states that allele frequencies (p, q) and genotype frequencies (p², 2pq, q²) remain constant generation after generation in a large, randomly mating population free from mutation, migration, and selection.

Genotype Frequencies vs Allele Frequency q
11100
x: Recessive allele frequency (q) · y: Genotype frequencyp² (AA)2pq (Aa)q² (aa)
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Try it: interactive calculator

Heterozygous carrier frequency (2pq)
0.42
= 2*(1-0.3)*0.3
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Step-by-step worked examples

In a population, the frequency of the recessive allele is q = 0.3. Find all genotype frequencies.

p = 1 − q = 1 − 0.3 = 0.7
p² = 0.7² = 0.49 (AA)
2pq = 2 × 0.7 × 0.3 = 0.42 (Aa)
q² = 0.3² = 0.09 (aa)

16% of a population shows the recessive phenotype (aa). Find the allele frequencies.

q² = 0.16 → q = √0.16 = 0.4
p = 1 − 0.4 = 0.6
2pq = 2 × 0.6 × 0.4 = 0.48 (carrier frequency)

In a population of 1,000 people, 90 are homozygous recessive (aa). Find the number of heterozygous carriers.

q² = 90/1000 = 0.09 → q = 0.3
p = 1 − 0.3 = 0.7
2pq = 2 × 0.7 × 0.3 = 0.42
Heterozygous individuals = 0.42 × 1000 = 420 people
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Flashcards

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Quick quiz

Q1.What does p² represent in the Hardy-Weinberg equation?

Correct answer: A. p² is the expected frequency of the AA (homozygous dominant) genotype.

Q2.If the frequency of the recessive allele is q = 0.2, what is p?

Correct answer: B. Since p + q = 1, p = 1 − 0.2 = 0.8.

Q3.Which of these is NOT a condition required for Hardy-Weinberg equilibrium?

Correct answer: C. Natural selection changes allele frequencies, so its absence is required for equilibrium.

Q4.A population has q² = 0.25 (frequency of aa individuals). What is q?

Correct answer: C. q = √0.25 = 0.5.
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Common mistakes

Thinking p and q are genotype frequencies.Correct: p and q are ALLELE frequencies; p², 2pq and q² are the genotype frequencies.

Forgetting that p + q must equal 1.Correct: Always check p + q = 1 before computing genotype frequencies.

Assuming any real population is in Hardy-Weinberg equilibrium.Correct: HWE is an idealized baseline — real populations almost always violate at least one assumption.

Believing any deviation from expected frequencies always means natural selection.Correct: Mutation, migration, genetic drift, or non-random mating can also cause a deviation, not just selection.

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FAQ

What is Hardy-Weinberg equilibrium?

It's a population genetics principle stating that allele and genotype frequencies stay constant across generations if no evolutionary forces act on the population.

What is the Hardy-Weinberg equilibrium formula?

p² + 2pq + q² = 1, where p and q are the frequencies of the dominant and recessive alleles (p + q = 1).

How do you calculate Hardy-Weinberg equilibrium?

Find q from the recessive phenotype frequency (q² ), then p = 1 − q, and compute p², 2pq, and q² for the genotype frequencies.

What are some Hardy-Weinberg equilibrium examples?

Calculating carrier frequency of a recessive disease allele, or predicting genotype ratios from a known phenotype ratio — see the worked examples above.

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