What are Faraday's Laws of Electrolysis?
Faraday's laws of electrolysis describe how electric charge drives chemical change. The first law links charge to moles of product; the second law compares products from different substances under the same charge.
Faraday's first law: moles of substance = Q / (nF), where Q is charge (C), n is electrons, F is Faraday's constant (96485 C/mol). Mass deposited is proportional to current and time.
- 1↓Apply current I (amperes)Charge flows through solution.
- 2↓Measure time t (seconds)Q = It (coulombs).
- 3↓Count electrons n per productCu²⁺ + 2e⁻ → Cu: n=2.
- 4↓Calculate molesmoles = Q/(nF) = It/(nF).
- 5Convert to massmass = moles × molar mass (g/mol).
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Step-by-step worked examples
Electrolyzing CuSO₄ with 2 A for 10 min, how many moles of Cu deposited? (n=2)
Q = It = 2 A × 600 s = 1200 C Cu²⁺ + 2e⁻ → Cu moles = Q/(nF) = 1200/(2×96485) moles = 1200/192970 = 0.00622 mol
If 0.5 mol of Ag deposits (1 e⁻ per Ag⁺), what charge passed?
Ag⁺ + e⁻ → Ag, so n=1 Q = moles × n × F Q = 0.5 × 1 × 96485 Q = 48242.5 C
Electrolyze AgNO₃ at 3 A for 5 min. How much Ag (M=107.9 g/mol) deposits?
Q = It = 3 × 300 = 900 C moles Ag = Q/(nF) = 900/(1×96485) = 0.00933 mol mass = 0.00933 × 107.9 = 1.007 g ≈ 1.01 g
Flashcards
Quick quiz
Q1.Moles of Cu deposited from CuSO₄ if Q = 1000 C and n = 2?
Q2.Which has the second law of electrolysis identified?
Q3.Faraday constant F equals…
Q4.Electrolyze for 1 hour at 1 A. If n=3, what is Q?
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Common mistakes
Faraday's law ignores the type of ion being electrolyzed. — Correct: Different ions deposit different masses for the same charge (second law).
Charge Q is just the current. — Correct: Charge is current × time: Q = It (in coulombs, not just amperes).
Faraday constant F is different for every experiment. — Correct: F = 96485 C/mol is a universal physical constant.
n is the number of moles deposited. — Correct: n is the number of electrons transferred per ion (e.g., Zn²⁺ needs 2e⁻).
FAQ
What are Faraday's laws of electrolysis?
First law: moles of product = Q/(nF). Second law: under equal charge, different ions deposit masses inversely proportional to their charge per ion.
How do I calculate moles from charge?
moles = Q/(nF), where Q is coulombs, n is electrons per ion, F is 96485 C/mol.
How do I find mass of metal deposited?
mass = moles × molar mass = [Q/(nF)] × M.
What is Faraday's second law?
Under the same charge, moles of different products are proportional to their (molar mass / charge per ion).




