🎓 Prepared by students from Boğaziçi University

What is Weak Acid and Weak Base Equilibrium?

Weak acids and bases only partially ionize in water, establishing dynamic equilibrium between molecular and ionic forms. The equilibrium constant Ka (for acids) or Kb (for bases) quantifies the extent of ionization.

Short answer

Weak acids: HA ⇌ H⁺ + A⁻, with Ka = [H⁺][A⁻]/[HA]. Weak bases: B + H₂O ⇌ BH⁺ + OH⁻, with Kb = [BH⁺][OH⁻]/[B]. Small Ka/Kb means weak ionization; large values mean stronger ionization.

Weak Acid Ionization Equilibrium
  1. 1
    1. Initial state
    Molecules (HA) dominate; few ions present
  2. 2
    2. Ionization
    Some HA splits: HA → H⁺ + A⁻
  3. 3
    3. Equilibrium
    Mostly HA left; small amounts of H⁺ and A⁻
  4. 4
    4. Equilibrium constant
    Ka = [H⁺][A⁻] / [HA] (small value)
01

Step-by-step worked examples

Acetic acid (CH₃COOH) is weak with Ka = 1.8 × 10⁻⁵. If [CH₃COOH]initial = 0.1 M, estimate [H⁺] at equilibrium.

Setup equilibrium: CH₃COOH ⇌ H⁺ + CH₃COO⁻
Ka = [H⁺][CH₃COO⁻]/[CH₃COOH] = 1.8 × 10⁻⁵
If x = [H⁺]: Ka = x²/(0.1 − x) ≈ x²/0.1 (since Ka is small)
x² = 1.8 × 10⁻⁶
x = [H⁺] ≈ 1.34 × 10⁻³ M

Ammonia (NH₃) is a weak base with Kb = 1.8 × 10⁻⁵. Compare to acetic acid's Ka.

Ammonia: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻, Kb = 1.8 × 10⁻⁵
Acetic acid: Ka = 1.8 × 10⁻⁵
Same Kb as Ka? Not quite—but both are weak (Ka, Kb < 10⁻³)

For a weak acid, why is [H⁺] less than the initial concentration?

Weak acids only partially ionize.
If initial [HA] = 0.1 M, only a fraction (e.g. 1%) ionizes.
[H⁺] from ionization << [HA]initial
This is why we can use approximation Ka ≈ x²/[HA]initial
02

Flashcards

03

Quick quiz

Q1.A weak acid has Ka = 0.001. Does it ionize significantly?

Correct answer: B. Ka = 0.001 = 10⁻³ is moderate. Very small Ka (< 10⁻⁶) = very weak; Ka > 0.1 = much stronger.

Q2.Hydrochloric acid (HCl) is strong; acetic acid (CH₃COOH) is weak. Why?

Correct answer: B. Strong acids dissociate 100%; weak acids establish equilibrium, staying mostly molecular.

Q3.For weak acid HA with Ka = 10⁻⁶, the equilibrium has mostly…

Correct answer: B. Very small Ka means little ionization; HA molecules dominate the equilibrium.

Q4.Ammonia (NH₃) is a weak base. Its conjugate acid (NH₄⁺) is…

Correct answer: A. Weak bases have weak conjugate acids; strong bases have weak conjugate acids (and vice versa).
📄Download this topic as a printable worksheet (PDF)Summary + 10 questions + answer key — print it, share it in class.
Study better with Bounlu apps
Notek
Notek

The full card deck, worked steps and AI-tutor support for “What is Weak Acid and Weak Base Equilibrium?” are in Notek — study by hand before your exam.

Get it free
Notek 1Notek 2Notek 3Notek 4Notek 5
04

Common mistakes

Weak acids don't produce H⁺.Correct: Weak acids do produce H⁺, but only partially; most stays as HA molecules.

Ka > Kb always.Correct: Ka and Kb for a conjugate pair are related by Kw; one large means the other is small.

Diluting a weak acid makes it ionize more (percent ionization goes down).Correct: Dilution increases percent ionization (more molecules split) but total [H⁺] decreases.

All monoprotic acids have Ka < 1.Correct: Strong monoprotic acids have Ka >> 1; weak acids have Ka < 1.

05

FAQ

What is the Ka constant?

Ka is the equilibrium constant for acid ionization: HA ⇌ H⁺ + A⁻. Small Ka = weak acid.

Why doesn't a weak acid fully ionize?

The reverse reaction (H⁺ + A⁻ → HA) is fast; equilibrium favors the molecular form if Ka is small.

How do I calculate [H⁺] for a weak acid?

Set up the equilibrium expression, use Ka = [H⁺][A⁻]/[HA], and solve (often using the quadratic formula or approximations).

Is water a weak acid or base?

Both! Water can act as a weak acid (Ka ≈ 10⁻¹⁶) or weak base (Kb ≈ 10⁻¹⁶).

Related topics