What is the Nernst Equation?
The Nernst equation calculates a cell's actual potential when concentrations differ from standard conditions. It shows how ions, reactants and products shift the voltage, predicting a cell's real-world output.
E = E° − (RT/nF)ln(Q), where E is actual potential, E° is standard potential, R is gas constant, T is temperature (K), n is electrons transferred, F is Faraday constant, and Q is reaction quotient.
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Step-by-step worked examples
Zn–Cu cell at 25°C, n=2, E°=1.10 V. If Q=4, what is E?
E = 1.10 − (8.314×298)/(2×96485)×ln(4) E = 1.10 − 0.02569×1.386 E = 1.10 − 0.0356 = 1.064 V
At equilibrium (Q=K), what is E?
When Q=K: ln(Q) = ln(K) E = E° − (RT/nF)×ln(K) = 0 V (The cell voltage is zero at equilibrium.)
Temperature doubles from 298 K to 596 K, Q=1, n=1, E°=0.5 V. New E?
E = 0.5 − (8.314×596)/(1×96485)×ln(1) ln(1)=0 so E = 0.5 V (At Q=1, E=E° regardless of T.)
Flashcards
Quick quiz
Q1.Nernst equation: E = E° − (RT/nF)ln(Q). At Q=1, E equals:
Q2.As Q increases (reaction progresses), E:
Q3.What is ln(Q) at equilibrium?
Q4.Doubling temperature T at Q=1 does what to E?
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Common mistakes
E = E° when Q = K. — Correct: E = 0 when Q = K (at equilibrium).
E increases as the cell discharges. — Correct: E decreases (voltage drops) as Q approaches K.
The Nernst equation only works at 25°C. — Correct: It works at any temperature; 0.0592 simplification is only at 25°C.
Higher temperature always increases E. — Correct: At Q=1 (standard), temperature doesn't affect E; only at other Q values.
FAQ
What is the Nernst equation formula?
E = E° − (RT/nF)ln(Q). It predicts actual cell potential from concentrations.
What does Q represent in the Nernst equation?
Q is the reaction quotient: [products]/[reactants] at current conditions.
Why does E drop as the reaction proceeds?
As Q increases toward equilibrium (K), the driving force (E) decreases to zero.
Simplified Nernst at 25°C?
E = E° − (0.0592/n)×log₁₀(Q) using base-10 log instead of natural log.




