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What Are Addition Reactions?

Addition reactions add atoms or groups to a C=C or C≡C bond, breaking the π-bond and forming two new σ-bonds. Electrophilic addition is most common with alkenes and alkynes. Understanding carbocation intermediates and Markovnikov's rule is essential for predicting products.

Short answer

In electrophilic addition, an electrophile attacks the π-electrons of an alkene, forming a carbocation intermediate. A nucleophile then adds to the carbocation. Markovnikov's rule states the electrophile adds to the carbon with more hydrogens, placing the nucleophile (or negative part) on the more substituted carbon.

Electrophilic Addition Mechanism (HBr to Alkene)
  1. 1
    Step 1: Electrophilic attack
    H⁺ (from HBr) attacks the π-electrons forming a carbocation (more stable one per Markovnikov).
  2. 2
    Step 2: Nucleophilic addition
    Br⁻ (nucleophile) attacks the carbocation from either face.
  3. 3
    Product: Alkyl halide
    C-H and C-Br bonds formed; π-bond replaced with two σ-bonds.
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Step-by-step worked examples

Draw the mechanism for HBr adding to propene (CH₃CH=CH₂). What is the major product?

Step 1: H⁺ attacks the π-bond. Two possible carbocations:
- Primary carbocation (less stable)
- Secondary carbocation from CH₃-CH⁺-CH₃ (more stable → formed)
Step 2: Br⁻ attacks the secondary carbocation
Product: CH₃CHBrCH₃ (2-bromopropane, major)
Minor: CH₃CH₂CH₂Br (1-bromopropane, very minor)

Predict the product of HBr + 2-methylpropene. Does rearrangement occur?

Substrate: (CH₃)₂C=CH₂ (2-methylpropene)
H⁺ attack forms a carbocation. Initially secondary (CH₃-C⁺-CH₂-CH₃ from β).
No rearrangement needed — secondary is already favorable.
Br⁻ attacks → product: (CH₃)₃C-Br (tert-butyl bromide, 2-bromo-2-methylpropane)
Follows Markovnikov.

What is the product of H₂O adding to 1-methylcyclohexene? Does carbocation rearrangement occur?

Substrate: cyclohexene ring with CH₃ at position 1
H⁺ attacks C=C forming a secondary benzylic-like carbocation.
H₂O attacks → product: major is the secondary alcohol (Markovnikov).
No rearrangement; secondary carbocation is stable enough.
Minor: primary alcohol from alternative attack.
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Flashcards

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Quick quiz

Q1.HCl + CH₃CH=CH₂ → major product?

Correct answer: B. H⁺ forms the secondary carbocation (CH₃CH⁺CH₃), Cl⁻ attacks → CH₃CHClCH₃ (Markovnikov).

Q2.Rank carbocation stability: 1°, 2°, 3°

Correct answer: B. Tertiary > secondary > primary. More alkyl substitution stabilizes the positive charge.

Q3.HBr + cyclohexene → major product's position of Br?

Correct answer: B. Symmetrical ring; either C (C1 or C2 in tautomeric sense) gives same 2° carbocation → HBr adds forming cyclohexyl bromide (2°).

Q4.Why does HBr + peroxides give anti-Markovnikov?

Correct answer: B. Peroxides initiate free-radical mechanism: Br-addition is to less substituted C (radical stability order opposite to carbocation).
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Common mistakes

Markovnikov's rule applies to all addition reactions.Correct: Markovnikov applies to electrophilic additions. Free-radical additions (HBr + peroxides) are anti-Markovnikov.

Primary carbocations are more stable than secondary.Correct: Secondary carbocations are more stable due to hyperconjugation from more alkyl groups.

Carbocation rearrangement always occurs.Correct: Rearrangement occurs only if it forms a more stable carbocation; many secondary/tertiary carbocations don't rearrange.

H₂O is a strong nucleophile in addition.Correct: H₂O is a weak nucleophile; it still attacks carbocations, but HBr and HCl react faster.

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FAQ

What is an addition reaction?

Atoms or groups add to a C=C or C≡C bond, converting π-bonds into σ-bonds and increasing saturation.

Why do electrophilic additions occur?

The π-electrons of C=C are polarizable and attract electrophiles (electron-poor species).

What happens in carbocation rearrangement?

A hydride or alkyl group shifts from an adjacent carbon to form a more stable carbocation before nucleophile attack.

Is the product always Markovnikov?

For ionic electrophilic additions, yes. But free-radical or other mechanisms can give anti-Markovnikov or different regioselectivity.

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