🎓 Prepared by students from Boğaziçi University

What is Infrared Spectroscopy?

Infrared (IR) spectroscopy uses infrared light to identify functional groups in molecules by detecting how they absorb specific IR wavelengths. Different bonds vibrate at different frequencies, creating a unique 'fingerprint' for each compound.

Short answer

IR spectroscopy measures the absorption of infrared light (wavelength 2.5–25 μm, wavenumber 400–4000 cm⁻¹) by molecular bonds, revealing functional groups present.

IR absorption frequency ranges for common bonds
3300247516508250
x: Functional group · y: Wavenumber (cm⁻¹)
01

Step-by-step worked examples

A compound shows a strong absorption peak at 1700 cm⁻¹. What functional group does this suggest?

1700 cm⁻¹ is in the C=O stretch region (carbonyl).
This indicates an aldehyde, ketone, carboxylic acid, ester, or amide.
Further analysis of other peaks (O-H at ~3300 cm⁻¹ for acid, or N-H) refines the identification.

Ethanol (CH₃CH₂OH) shows peaks at 2900 (C-H), 3300 (O-H), and 1050 (C-O) cm⁻¹. Explain each peak.

2900 cm⁻¹: C-H stretching (alkyl groups)
3300 cm⁻¹: O-H stretching (hydroxyl group, broad peak)
1050 cm⁻¹: C-O stretching (alcohol C-O bond)
These peaks confirm ethanol's functional groups.

Phenol (C₆H₅OH) shows a O-H peak at 3200 cm⁻¹, not 3300. Why might it differ from aliphatic alcohols?

Phenol's O-H is directly bonded to an aromatic ring.
The aromatic structure shifts the O-H stretching frequency slightly.
Hydrogen bonding in phenol can also broaden the peak and shift it to lower frequency.
02

Flashcards

03

Quick quiz

Q1.A spectrum shows a strong, sharp peak at 2150 cm⁻¹. Which bond is this likely?

Correct answer: C. 2150 cm⁻¹ is characteristic of C≡N (nitrile/cyano) stretching.

Q2.IR peaks for O-H in carboxylic acids are typically…

Correct answer: B. Hydrogen bonding in carboxylic acids broadens the O-H peak significantly.

Q3.What does a C=O peak at ~1650 cm⁻¹ suggest, rather than 1700 cm⁻¹?

Correct answer: B. Amides show lower C=O frequency (~1650 cm⁻¹) due to C-N resonance and conjugation.

Q4.Why is the fingerprint region (below 1500 cm⁻¹) useful?

Correct answer: B. Complex skeletal vibrations make the fingerprint region unique for each compound.
📄Download this topic as a printable worksheet (PDF)Summary + 10 questions + answer key — print it, share it in class.
Study better with Bounlu apps
Notek
Notek

The full card deck, worked steps and AI-tutor support for “What is Infrared Spectroscopy?” are in Notek — study by hand before your exam.

Get it free
Notek 1Notek 2Notek 3Notek 4Notek 5
04

Common mistakes

IR spectroscopy identifies the actual structure of a compound.Correct: IR identifies functional groups present, not full structure — NMR and MS are needed for complete structure.

All C=O bonds absorb at exactly 1700 cm⁻¹.Correct: C=O frequency varies (1650 cm⁻¹ for amides, 1750 cm⁻¹ for acid chlorides) due to conjugation and hybridization.

Wavenumber is the same as wavelength.Correct: Wavenumber (cm⁻¹) = 1/wavelength (cm); they are inversely related.

Broad peaks are always due to hydrogen bonding.Correct: Broad peaks usually indicate hydrogen bonding, but can also result from multiple vibrational modes.

05

FAQ

What does 'IR-active' mean?

A bond is IR-active if its vibration changes the molecular dipole moment, allowing it to absorb IR light.

Why does solvent choice matter in IR spectroscopy?

Solvents like KBr and CCl₄ are used for solid/liquid samples. Some solvents absorb IR and mask peak regions.

Can IR spectroscopy detect all functional groups?

No — symmetrical groups (like C=C in nonpolar alkenes) may not show IR absorption; NMR is better for these.

What is an 'IR-inactive' group?

A group whose vibration does not change the dipole moment (e.g. symmetrical diatomic molecules like O₂).

Related topics