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What is a Rate Law and Reaction Order?

A rate law expresses reaction rate as a mathematical function of reactant concentrations: rate = k[A]^m[B]^n. The exponents m and n are reaction orders; they determine how sensitive the rate is to concentration changes.

Short answer

Rate law: rate = k[A]^m[B]^n, where k is the rate constant and m, n are the reaction orders. Orders are determined experimentally, not from stoichiometry.

Rate vs. [A] for different reaction orders
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x: [A] (mol/L) · y: Rate (mol/(L·s))Zero order (m=0): rate ∝ [A]^0First order (m=1): rate ∝ [A]^1Second order (m=2): rate ∝ [A]^2
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Try it: interactive calculator

Reaction rate
0.125mol/(L·s)
= 0.5 * (0.5 ** 1) * (0.5 ** 1)
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Step-by-step worked examples

For a reaction rate = k[A][B], with k = 0.5 M^-1·s^-1, [A] = 2 M, [B] = 0.3 M, find the rate.

rate = k[A][B]
rate = 0.5 × 2 × 0.3
rate = 0.3 mol/(L·s)

A decomposition follows rate = k[A]^2 with k = 0.02 M^-1·s^-1 and [A] = 1.5 M. Rate?

rate = k[A]^2
rate = 0.02 × (1.5)^2
rate = 0.02 × 2.25 = 0.045 mol/(L·s)

If doubling [A] quadruples the rate, what is the reaction order with respect to A?

If rate ∝ [A]^m, and 2[A] → 4 × rate
Then 2^m = 4
2^m = 2^2, so m = 2
The reaction is second order in A.
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Flashcards

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Quick quiz

Q1.For rate = 0.1[A]^2[B], if [A] = 2 M and [B] = 1 M, rate?

Correct answer: C. rate = 0.1 × (2)^2 × 1 = 0.1 × 4 = 0.4 mol/(L·s).

Q2.Tripling [A] increases rate 9×. Reaction order in A?

Correct answer: C. 3^m = 9 → m = 2 (second order).

Q3.Which is determined experimentally?

Correct answer: C. Both k and orders come from experiment, not from the balanced equation.

Q4.For a zero-order reaction, doubling [A]…

Correct answer: C. rate = k[A]^0 = k (constant), independent of [A].
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Common mistakes

Reaction order comes from the balanced equation coefficients.Correct: Order is determined experimentally; it may differ from stoichiometry in complex reactions.

Rate constant k is always the same for a reaction.Correct: k depends on temperature; it increases with increasing T.

All reactions are first or second order.Correct: Reactions can be zero, fractional, or even complex orders depending on mechanism.

Higher order = faster reaction.Correct: Order describes concentration sensitivity; a zero-order reaction rate is independent of [A].

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FAQ

How do you determine the reaction order from data?

Use the method of initial rates or integrated rate laws. Compare rates as [A] varies; if rate ∝ [A]^m, m is the order.

Why is rate law determined experimentally, not from stoichiometry?

Because not all reactants participate at the same stage; rate laws reflect the reaction mechanism.

What are the units of the rate constant k?

Units depend on overall order: zero-order k has units mol/(L·s); first-order k has units s^-1; second-order k has units L/(mol·s).

Can a rate law have negative or fractional orders?

Fractional orders are possible (e.g., 0.5, 1.5) and indicate complex mechanisms. Negative orders are rare but can occur in special systems.

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